1836 United States presidential election in Illinois

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1836 United States presidential election in Illinois
Flag of Illinois.svg
  1832 November 7, 1836 1840  
  GA
IN  
  Martin Van Buren circa 1837 crop.jpg William Henry Harrison by James Reid Lambdin, 1835 crop.jpg
Nominee Martin Van Buren William Henry Harrison
Party Democratic Whig
Home state New York Ohio
Running mate Richard M. Johnson Francis Granger
Electoral vote50
Popular vote18,36915,220
Percentage54.69%45.31%

Illinois Presidential Election Results 1836.svg
County Results

A presidential election was held in Illinois on November 7, 1836 as part of the 1836 United States presidential election. [1] Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.

Contents

Illinois voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won Illinois by a margin of 9.38%.

Harrison won Chicago by six votes. [2]

Results

1836 United States presidential election in Illinois [3]
PartyCandidateVotesPercentageElectoral votes
Democratic Martin Van Buren 18,36954.69%5
Whig William Henry Harrison 15,22045.31%0
Totals33,589100.0%5

See also

References

  1. "Presidential Elections". Weekly Messenger. November 12, 1836.
  2. Merriner 2004, p. 21.
  3. "1836 Presidential General Election Results - Illinois". U.S. Election Atlas. Retrieved August 4, 2012.

Works cited