1836 United States presidential election in Illinois

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1836 United States presidential election in Illinois
Flag of Illinois.svg
  1832 November 3 – December 7, 1836 1840  
  Martin Van Buren circa 1837 crop.jpg William Henry Harrison by James Reid Lambdin, 1835 crop.jpg
Nominee Martin Van Buren William Henry Harrison
Party Democratic Whig
Home state New York Ohio
Running mate Richard Johnson Francis Granger
Electoral vote50
Popular vote18,36915,220
Percentage54.69%45.31%

The 1836 United States presidential election in Illinois took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.

Contents

Illinois voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won Illinois by a margin of 9.38%. This is the last time Ogle County voted Democratic.

Results

1836 United States presidential election in Illinois [1]
PartyCandidateVotesPercentageElectoral votes
Democratic Martin Van Buren 18,36954.69%5
Whig William Henry Harrison 15,22045.31%0
Totals33,589100.0%5

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References

  1. "1836 Presidential General Election Results - Illinois". U.S. Election Atlas. Retrieved 4 August 2012.