1836 United States presidential election in Kentucky

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1836 United States presidential election in Kentucky
  1832 November 3 – December 7, 1836 1840  
  William Henry Harrison by James Reid Lambdin, 1835 crop.jpg Martin Van Buren circa 1837 crop.jpg
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate Francis Granger Richard Johnson
Electoral vote150
Popular vote36,86133,229
Percentage52.59%47.41%

The 1836 United States presidential election in Kentucky took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.

Kentucky voted for Whig candidate William Henry Harrison over the Democratic candidate, Martin Van Buren. Harrison won Kentucky by a margin of 5.18%.

Results

United States presidential election in Kentucky, 1836 [1]
PartyCandidateVotesPercentageElectoral votes
Whig William Henry Harrison 36,86152.59%15
Democratic Martin Van Buren 33,22947.41%0
Totals70,090100.0%15

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References

  1. "1836 Presidential General Election Results - Kentucky". U.S. Election Atlas. Retrieved August 4, 2012.