1836 United States presidential election in Louisiana

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1836 United States presidential election in Louisiana
Flag of Louisiana.svg
  1832 November 8, 1836 1840  
  NY
AL  
  Martin Van Buren circa 1837 crop.jpg HLWhite.jpg
Nominee Martin Van Buren Hugh L. White
Party Democratic Whig
Home state New York Tennessee
Running mate Richard M. Johnson John Tyler
Electoral vote50
Popular vote3,8423,583
Percentage51.74%48.26%

President before election

Andrew Jackson
Democratic

Elected President

Martin Van Buren
Democratic

A presidential election was held in Louisiana on November 8, 1836 as part of the 1836 United States presidential election. [1] Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.

Contents

Louisiana voted for the Democratic candidate, Martin Van Buren, over Whig candidate Hugh White. Van Buren won Louisiana by a narrow margin of 3.48%.

Results

1836 United States presidential election in Louisiana [2]
PartyCandidateVotesPercentageElectoral votes
Democratic Martin Van Buren 3,84251.74%5
Whig Hugh White 3,58348.26%0
Totals7,425100.0%5

See also

References

  1. "Presidential Elections". Weekly Messenger. November 12, 1836.
  2. "1836 Presidential General Election Results - Louisiana". U.S. Election Atlas. Retrieved August 4, 2012.