1836 United States presidential election in Louisiana

Main article: 1836 United States presidential election

1836 United States presidential election in Louisiana

←  1832 November 8, 1836 1840  →

←  NY AL  →

Nominee Martin Van Buren Hugh L. White Party Democratic Whig Home state New York Tennessee Running mate Richard M. Johnson John Tyler Electoral vote 5 0 Popular vote 3,842 3,583 Percentage 51.74% 48.26%

Parish results Van Buren   50–60%   60–70%   70–80%   80–90%   90–100% White   50–60%   60–70%   70–80%   80–90% Tie/No Data

President before election Andrew Jackson Democratic Elected President Martin Van Buren Democratic

A presidential election was held in Louisiana on November 8, 1836 as part of the 1836 United States presidential election. ^[1] Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.

Louisiana voted for the Democratic candidate, Martin Van Buren, over Whig candidate Hugh White. Van Buren won Louisiana by a narrow margin of 3.48%.

Results

1836 United States presidential election in Louisiana [2]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	Martin Van Buren	3,842	51.74%	5
	Whig	Hugh White	3,583	48.26%	0
Totals			7,425	100.0%	5

See also

• United States presidential elections in Louisiana

References

1. "Presidential Elections". Weekly Messenger. November 12, 1836.
2. "1836 Presidential General Election Results - Louisiana". U.S. Election Atlas. Retrieved August 4, 2012.