1836 United States presidential election in Delaware

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1836 United States presidential election in Delaware
Flag of Delaware.svg
  1832 November 7, 1836 1840  
  CT
GA  
  William Henry Harrison by James Reid Lambdin, 1835 crop.jpg Martin Van Buren circa 1837 crop.jpg
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate Francis Granger Richard M. Johnson
Electoral vote30
Popular vote4,7364,154
Percentage53.24%46.70%

Delaware Presidential Election Results 1836.svg
County Results

President before election

Andrew Jackson
Democratic

Elected President

Martin Van Buren
Whig

The 1836 United States presidential election in Delaware was held on November 7, 1836 as part of the 1836 United States presidential election. [1] Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

Contents

Delaware voted for Whig candidate William Henry Harrison over the Democratic candidate, Martin Van Buren. Harrison won Delaware by a margin of 6.54%.

Results

1836 United States presidential election in Delaware [2]
PartyCandidateVotesPercentageElectoral votes
Whig William Henry Harrison 4,73653.24%3
Democratic Martin Van Buren 4,15446.70%0
N/AOther50.06%0
Totals8,895100.00%3

Results by county

1836 United States presidential election in Delaware [3]
CountyWilliam Henry Harrison

Whig

Martin Van Buren

Democratic

Various candidates

Other parties

MarginTotal votes cast
#%#%#%#%
Kent1,20553.70%1,03946.30%00.00%1667.40%2,244
New Castle1,67347.91%1,81451.95%50.14%-141-4.04%3,492
Sussex1,85858.82%1,30141.18%00.00%55717.63%3,159
Total:4,73653.24%4,15446.70%50.06%5826.54%8,895

See also

References

  1. "Presidential Elections". Weekly Messenger. November 12, 1836.
  2. "1836 Presidential General Election Results - Delaware". U.S. Election Atlas. Retrieved August 4, 2012.
  3. Burnham, Walter Dean (1955). Presidential ballots, 1836-1892. Internet Archive. Baltimore, Johns Hopkins Press. p. 320.