1896 United States presidential election in Delaware

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1896 United States presidential election in Delaware
Flag of Delaware.svg
  1892 November 3, 1896 1900  
  William McKinley by Courtney Art Studio, 1896 (cropped).jpg William Jennings Bryan 2 (cropped).jpg
Nominee William McKinley William Jennings Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate Garret Hobart Arthur Sewall
Electoral vote30
Popular vote20,45016,574
Percentage53.18%43.10%

Delaware Presidential Election Results 1896.svg
County Results
McKinley
  50–60%


President before election

Grover Cleveland
Democratic

Elected President

William McKinley
Republican

The 1896 United States presidential election in Delaware took place on November 3, 1896. All contemporary 45 states were part of the 1896 United States presidential election. State voters chose three electors to the Electoral College, which selected the president and vice president.

Contents

Delaware was won by the Republican nominees, former Ohio Governor William McKinley and his running mate Garret Hobart of New Jersey. They defeated the Democratic nominee, former U.S. Representative from Nebraska William Jennings Bryan and his running mate Arthur Sewall. McKinley won the state by a margin of 10.08%.

As a result of his win in Delaware, McKinley became the first Republican presidential candidate since Ulysses S. Grant in 1872 to win the state.

Bryan would lose Delaware to McKinley again four years later and would later lose the state again in 1908 to William Howard Taft.

Results

1896 United States presidential election in Delaware [1]
PartyCandidateVotesPercentageElectoral votes
Republican William McKinley 20,45053.18%3
Democratic William Jennings Bryan 16,57443.10%0
National Democratic John M. Palmer 9662.51%0
Prohibition Joshua Levering 4661.21%0
Totals38,456100.00%3
Voter turnout

See also

Notes

    References

    1. Dave Leip's U.S. Election Atlas; Presidential General Election Results – Delaware