1808 United States presidential election in Delaware

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1808 United States presidential election in Delaware
Flag of Delaware.svg
  1804 4 November – 7 December 1808 1812  
  CharlesCPinckney (cropped).png James Madison.jpg
Nominee Charles C. Pinckney James Madison
Party Federalist Democratic-Republican
Home state South Carolina Virginia
Running mate Rufus King George Clinton
Electoral vote30

The 1808 United States presidential election in Delaware took place between 4 November and 7 December 1808, as part of the 1808 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

Contents

Delaware cast three electoral votes for the Federalist candidate Charles C. Pinckney over the Democratic-Republican candidate James Madison. These electors were elected by the Delaware General Assembly, the state legislature, rather than by popular vote. The three electoral votes for Vice president were cast for Pinckney's running mate Rufus King from New York. [1]

Results

1808 United States presidential election in Delaware [2]
PartyCandidateVotesPercentageElectoral votes
Federalist Charles C. Pinckney 3
Democratic-Republican James Madison 0
Totals3

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References

  1. "1808 Presidential General Election Results". U.S. Election Atlas. Retrieved July 9, 2023.
  2. "1808 Presidential Election". 270towin.com. Retrieved July 9, 2023.