1808 United States presidential election in Delaware

Main article: 1808 United States presidential election

1808 United States presidential election in Delaware

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Nominee Charles C. Pinckney James Madison Party Federalist Democratic-Republican Home state South Carolina Virginia Running mate Rufus King George Clinton Electoral vote 3 0

The 1808 United States presidential election in Delaware took place between 4 November and 7 December 1808, as part of the 1808 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

Delaware cast three electoral votes for the Federalist candidate Charles C. Pinckney over the Democratic-Republican candidate James Madison. These electors were elected by the Delaware General Assembly, the state legislature, rather than by popular vote. The three electoral votes for Vice president were cast for Pinckney's running mate Rufus King from New York. ^[1]

Results

1808 United States presidential election in Delaware [2]
Party		Candidate	Votes	Percentage	Electoral votes
	Federalist	Charles C. Pinckney	–	–	3
	Democratic-Republican	James Madison	–	–	0
Totals			–	–	3

See also

• United States presidential elections in Delaware

References

1. "1808 Presidential General Election Results". U.S. Election Atlas. Retrieved July 9, 2023.
2. "1808 Presidential Election". 270towin.com. Retrieved July 9, 2023.