1804 United States presidential election in Delaware

Last updated

1804 United States presidential election in Delaware
Flag of Delaware.svg
  1800 2 November – 5 December 1804 1808  
  CharlesCPinckney (cropped).png Thomas Jefferson by Rembrandt Peale, 1800.jpg
Nominee Charles Cotesworth Pinckney Thomas Jefferson
Party Federalist Democratic-Republican
Home state South Carolina Virginia
Running mate Rufus King George Clinton
Electoral vote30

The 1804 United States presidential election in Delaware took place between November 2 and December 5, 1804, as part of the 1804 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

Contents

Delaware cast three electoral votes for the Federalist candidate Charles Cotesworth Pinckney over the Democratic-Republican candidate and incumbent President Thomas Jefferson. These electors were elected by the Delaware General Assembly, the state legislature, rather than by popular vote. The three electoral votes for Vice president were cast for Pinckney's running mate Rufus King from New York. [1]

Results

1804 United States presidential election in Delaware [2]
PartyCandidateVotesPercentageElectoral votes
Federalist Charles Cotesworth Pinckney 3
Democratic-Republican Thomas Jefferson (incumbent)0
Totals3

See also

References

  1. "1804 Presidential General Election Results". U.S. Election Atlas. Retrieved July 9, 2023.
  2. "1804 Presidential Election". 270towin.com. Retrieved July 9, 2023.