1804 United States presidential election in Delaware

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1804 United States presidential election in Delaware
Flag of Delaware.svg
  1800 November 2 – December 5, 1804 1808  
  James Earl - General Charles Cotesworth Pinckney - Google Art Project (3x4 cropped b).jpg
Nominee Charles Cotesworth Pinckney
Party Federalist
Home state South Carolina
Running mate Rufus King
Electoral vote3

The 1804 United States presidential election in Delaware took place between November 2 and December 5, 1804, as part of the 1804 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

Contents

Delaware cast three electoral votes for the Federalist candidate Charles Cotesworth Pinckney over the Democratic-Republican candidate and incumbent President Thomas Jefferson. These electors were elected by the Delaware General Assembly, the state legislature, rather than by popular vote. The three electoral votes for Vice president were cast for Pinckney's running mate Rufus King from New York. [1]

Results

1804 United States presidential election in Delaware [2]
PartyCandidateVotesPercentageElectoral votes
Federalist Charles Cotesworth Pinckney 3
Democratic-Republican Thomas Jefferson (incumbent)0
Totals3

See also

References

  1. "1804 Presidential General Election Results". U.S. Election Atlas. Retrieved 2023-07-09.
  2. "1804 Presidential Election". 270towin.com. Retrieved 2023-07-09.