1792 United States presidential election in Delaware

Last updated

1792 United States presidential election in Delaware
Flag of Delaware.svg
  1788–89 November 2 – December 5, 1792 1796  
  George Washington Portrait (3x4 cropped).jpg Official Presidential portrait of John Adams (by John Trumbull, circa 1792) (farther 3x4 cropped) (cropped).jpg
Nominee George Washington John Adams
Party Independent Federalist
Home state Virginia Massachusetts
Electoral vote33
Percentage100.00%

President before election

George Washington
Independent

Elected President

George Washington
Independent

The 1792 United States presidential election in Delaware took place between November 2 and December 5, 1792, as part of the 1792 United States presidential election. The state legislature chose three members of the Electoral College, each of whom, under the provisions of the Constitution prior to the passage of the Twelfth Amendment, cast two votes for President.

Contents

Delaware's three electors each cast one vote for the incumbent, George Washington, and one vote for John Adams, the incumbent Vice President. [1]

Results

1792 United States presidential election in Delaware
PartyCandidateVotesPercentageElectoral votes
Independent George Washington (incumbent)100.00%3
Totals100.00%3

See also

References

  1. 1792 Presidential Electoral Vote Count Dave Leip's Atlas of U.S. Presidential Elections.