1880 United States presidential election in Delaware

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1880 United States presidential election in Delaware
Flag of Delaware.svg
  1876 November 2, 1880 1884  
  WinfieldScottHancock2 (cropped 3x4).jpg James Abram Garfield, photo portrait seated (cropped).jpg
Nominee Winfield S. Hancock James A. Garfield
Party Democratic Republican
Home state Pennsylvania Ohio
Running mate William H. English Chester A. Arthur
Electoral vote30
Popular vote15,18114,148
Percentage51.53%48.03%

Delaware Presidential Election Results 1880.svg
County Results

President before election

Rutherford B. Hayes
Republican

Elected President

James Garfield
Republican

The 1880 United States presidential election in Delaware took place on November 2, 1880, as part of the 1880 United States presidential election. State voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president. [1]

Contents

Delaware was won by General Winfield Scott Hancock (DPennsylvania), running with former Representative William Hayden English, with 51.53% of the popular vote, against Representative James A. Garfield (R-Ohio), running with the 10th chairman of the New York State Republican Executive Committee Chester A. Arthur, with 48.03% of the vote. [1]

As of 2023, this is the most recent time that a Republican won the presidency without carrying Sussex County.

Results

1880 United States presidential election in Delaware [1]
PartyCandidateRunning matePopular voteElectoral vote
Count%Count%
Democratic Winfield Scott Hancock of Pennsylvania William Hayden English of Indiana 15,18151.53%3100.00%
Republican James A. Garfield of Ohio Chester A. Arthur of New York 14,14848.03%00.00%
Greenback James B. Weaver of Iowa Barzillai J. Chambers of Texas 1290.44%00.00%
Total18,345100.00%3100.00%

See also

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References

  1. 1 2 3 "1880 Presidential Election Results Delaware".