1880 United States presidential election in Florida

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1880 United States presidential election in Florida
Flag of Florida (1868-1900).svg
  1876 November 2, 1880 1884  
Turnout19.15% of the total population Decrease2.svg 5.77 pp [1]
  WinfieldScottHancock2 (cropped 3x4).jpg James Abram Garfield, photo portrait seated (cropped).jpg
Nominee Winfield S. Hancock James A. Garfield
Party Democratic Republican
Home state Pennsylvania Ohio
Running mate William H. English Chester A. Arthur
Electoral vote40
Popular vote27,96423,654
Percentage54.17%45.83%

Florida Presidential Election Results 1880.svg
County Results

President before election

Rutherford B. Hayes
Republican

Elected President

James Garfield
Republican

The 1880 United States presidential election in Florida took place on November 2, 1880, as part of the 1880 United States presidential election. Florida voters chose four representatives, or electors, to the Electoral College, who voted for president and vice president. [2]

Contents

Florida was won by General Winfield Scott Hancock (DPennsylvania), running with former Representative William Hayden English, with 54.17% of the popular vote, against Representative James Garfield (R-Ohio), running with the 10th chairman of the New York State Republican Executive Committee Chester A. Arthur, with 41.05% of the vote. [2]

Results

United States presidential election in Florida, 1880 [2]
PartyCandidateRunning matePopular voteElectoral vote
Count%Count%
Democratic Winfield Scott Hancock of Pennsylvania William Hayden English of Indiana 27,96454.17%4100.00%
Republican James Garfield of Ohio Chester A. Arthur of New York 23,65445.83%00.00%
Total51,618100.00%4100.00%

See also

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References

  1. "1884 Presidential Election Results Florida Total Population Turnout".
  2. 1 2 3 "1880 Presidential Election Results Florida".