1804 United States presidential election in Kentucky

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1804 United States presidential election in Kentucky
  1800 November 2 – December 15, 1804 1808  
  Thomas Jefferson by Rembrandt Peale, 1800.jpg CharlesCPinckney (cropped).png
Nominee Thomas Jefferson Charles Cotesworth Pinckney
Party Democratic-Republican Federalist
Home state Virginia South Carolina
Running mate George Clinton Rufus King
Electoral vote80
Popular vote5,0800
Percentage100.00%0.00%

The 1804 United States presidential election in Kentucky took place between November 2 and December 15, 1804, as part of the 1804 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President. Kentucky had gained four electors compared to the previous election in 1800. [1]

Contents

Kentucky cast eight electoral votes for the Democratic-Republican candidate and incumbent President Thomas Jefferson over the Federalist candidate Charles Cotesworth Pinckney. The electoral votes for Vice president were cast for Jefferson's running mate George Clinton from New York. The state was divided into two electoral districts with four electors each, whereupon each district's voters chose the electors. [2]

Results

1804 United States presidential election in Kentucky [3]
PartyCandidateVotesPercentageElectoral votes
Democratic-Republican Thomas Jefferson (incumbent)5,080100.0%8
Federalist Charles Cotesworth Pinckney 00.00%0
Totals5,080100.0%8

See also

References

  1. "A New Nation Votes". elections.lib.tufts.edu. Retrieved July 14, 2023.
  2. "1804 Presidential General Election Results". U.S. Election Atlas. Retrieved July 14, 2023.
  3. "1804 Presidential Election". 270towin.com. Retrieved July 14, 2023.