1804 United States presidential election in Ohio

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1804 United States presidential election in Ohio
Flag of Ohio.svg
1808  →
  Thomas Jefferson by Rembrandt Peale, 1800.jpg CharlesCPinckney (cropped).png
Nominee Thomas Jefferson Charles Cotesworth Pinckney
Party Democratic-Republican Federalist
Home state Virginia South Carolina
Running mate George Clinton Rufus King
Electoral vote30
Popular vote2,593364
Percentage87.69%12.31%
President before election

Thomas Jefferson
Democratic-Republican

Elected President

Thomas Jefferson
Democratic-Republican

The 1804 United States presidential election in Ohio took place as part of the 1804 United States presidential election. Voters chose three representatives, or electors, to vote for president and vice president. It was the first time that Ohio took part in a United States presidential election, as it had been admitted as the 17st of the Union on March 1, 1803.

Results

1804 United States presidential election in Ohio [1]
PartyCandidateVotesPercentageElectoral votes
Democratic-Republican Thomas Jefferson (incumbent)2,59387.69%3
Federalist Charles Cotesworth Pinckney 36412.31%0
Totals2,957100.0%3

References

  1. ↑ "A New Nation Votes". elections.lib.tufts.edu. Retrieved July 3, 2023.


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