1836 United States presidential election in Massachusetts

Main article: 1836 United States presidential election

1836 United States presidential election in Massachusetts

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Turnout	43.4% [1] 4.0 pp
Nominee Daniel Webster Martin Van Buren Party Whig Democratic Home state Massachusetts New York Running mate Francis Granger Richard M. Johnson Electoral vote 14 0 Popular vote 41,201 33,486 Percentage 55.13% 44.81%
County results Webster   50–60%   60–70% Van Buren   50–60%

A presidential election was held in Massachusetts on November 14, 1836 as part of the 1836 United States presidential election. ^[2] Voters chose 14 representatives, or electors to the Electoral College, who voted for President and Vice President.

Massachusetts voted for Whig candidate and state native Daniel Webster over the Democratic candidate, Martin Van Buren. Webster won Massachusetts by a margin of 10.32%.

In a unique strategy to throw the election into the House of Representatives, the Whigs ran four different candidates in different sections of the United States. This is the only state in which Daniel Webster was on the ballot. ^[3]

Results

1836 United States presidential election in Massachusetts [4]
Party		Candidate	Votes	Percentage	Electoral votes
	Whig	Daniel Webster	41,201	55.13%	14
	Democratic	Martin Van Buren	33,486	44.81%	0
	N/A	Other	45	0.06%	0
Totals			74,732	100.00%	14

See also

• United States presidential elections in Massachusetts

References

1. Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
2. "Presidential Elections". Weekly Messenger. November 12, 1836.
3. "Presidential Election of 1836 - 270toWin". 270toWin.com. Retrieved August 4, 2022.
4. "1836 Presidential General Election Results - Massachusetts". U.S. Election Atlas. Retrieved August 4, 2012.