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County Results
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Elections in Indiana |
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The 1836 United States presidential election in Indiana took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for President and Vice President.
Indiana voted for Whig candidate William Henry Harrison over the Democratic candidate, Martin Van Buren. Harrison won Indiana by a margin of 11.94%.
1836 United States presidential election in Indiana [1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Whig | William Henry Harrison | 41,281 | 55.97% | 9 | |
Democratic | Martin Van Buren | 32,478 | 44.03% | 0 | |
Totals | 73,759 | 100.0% | 9 | ||
The 1836 United States presidential election was the 13th quadrennial presidential election, held from Thursday, November 3 to Wednesday, December 7, 1836. In the third consecutive election victory for the Democratic Party, incumbent Vice President Martin Van Buren defeated four candidates fielded by the nascent Whig Party.
The 1840 United States presidential election was the 14th quadrennial presidential election, held from Friday, October 30 to Wednesday, December 2, 1840. Economic recovery from the Panic of 1837 was incomplete, and Whig nominee William Henry Harrison defeated incumbent President Martin Van Buren of the Democratic Party. The election marked the first of two Whig victories in presidential elections, but was the only one where they won a majority of the popular vote. This was the third rematch in American history, which would not occur again until 1892.
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