1889 Chicago mayoral election

1889 Chicago mayoral election

←  1887 April 2, 1889 1891  →

Nominee DeWitt Clinton Cregier John A. Roche Party Democratic Republican Popular vote 57,340 46,328 Percentage 54.93% 44.38%

Mayor before election John A. Roche Republican Elected mayor DeWitt Clinton Cregier Democratic

In the Chicago mayoral election of 1889, Democrat DeWitt Clinton Cregier defeated incumbent Republican John A. Roche, winning a majority of the vote and a margin of victory in excess of ten percent.

The election was held on April 2, 1889. ^{[1] [2]}

Campaign

Cregier backed strongly by trade unions. ^[3] John Peter Altgeld threw his backing behind Cregier's candidacy. ^[3]

Results

1889 Chicago mayoral election ^[1]

Party		Candidate	Votes	%
	Democratic	DeWitt Clinton Cregier	57,340	54.93
	Republican	John A. Roche (incumbent)	46,328	44.38
	Prohibition	Ira J. Mason	410	0.39
	Socialist Labor	Charles Orchardson	303	0.29
Turnout			104,381

Creiger received 76.86% of the Polish-American vote, while Roche received 23.07%. ^[4]

References

1. The Chicago Daily News Almanac and Year Book for 1912. Chicago Daily News, Incorporated. 1911. p. 464. Retrieved May 12, 2020.
2. Currey, Josiah Seymour (1912). Chicago: Its History and Its Builders, a Century of Marvelous Growth. S. J. Clarke publishing Company. p.  335.
3. Kersten, Andrew E. (2011). Clarence Darrow: American Iconoclast. Macmillan. p. 46. ISBN   978-0-8090-9486-8 . Retrieved June 2, 2020.
4. Kantowicz, Edward (1972). "The Emergence of the Polish-Democratic Vote in Chicago". Polish American Studies. 29 (1/2): 67–80. JSTOR   20147849.