1889 Chicago mayoral election

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1889 Chicago mayoral election
  1887 April 2, 1889 1891  
  DeWitt Clinton Cregier old portrait (1).jpg John Roche (1).jpg
Nominee DeWitt Clinton Cregier John A. Roche
Party Democratic Republican
Popular vote57,34046,328
Percentage54.93%44.38%

Mayor before election

John A. Roche
Republican

Elected mayor

DeWitt Clinton Cregier
Democratic

In the Chicago mayoral election of 1889, Democrat DeWitt Clinton Cregier defeated incumbent Republican John A. Roche, winning a majority of the vote and a margin of victory in excess of ten percent.

Contents

The election was held on April 2, 1889. [1] [2]

Campaign

Cregier backed strongly by trade unions. [3] John Peter Altgeld threw his backing behind Cregier's candidacy. [3]

Results

1889 Chicago mayoral election [1]
PartyCandidateVotes%
Democratic DeWitt Clinton Cregier 57,340 54.93
Republican John A. Roche (incumbent)46,32844.38
Prohibition Ira J. Mason4100.39
Socialist Labor Charles Orchardson3030.29
Turnout 104,381

Creiger received 76.86% of the Polish-American vote, while Roche received 23.07%. [4]

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References

  1. 1 2 The Chicago Daily News Almanac and Year Book for 1912. Chicago Daily News, Incorporated. 1911. p. 464. Retrieved May 12, 2020.
  2. Currey, Josiah Seymour (1912). Chicago: Its History and Its Builders, a Century of Marvelous Growth. S. J. Clarke publishing Company. p.  335.
  3. 1 2 Kersten, Andrew E. (2011). Clarence Darrow: American Iconoclast. Macmillan. p. 46. ISBN   978-0-8090-9486-8 . Retrieved June 2, 2020.
  4. Kantowicz, Edward (1972). "The Emergence of the Polish-Democratic Vote in Chicago". Polish American Studies. 29 (1/2): 67–80. JSTOR   20147849.