1796 United States presidential election in New Hampshire

Last updated

1796 United States presidential election in New Hampshire
Flag of New Hampshire.svg
  1792 November 4 – December 7, 1796 1800  
  Gilbert Stuart, John Adams, c. 1800-1815, NGA 42933.jpg Thomas Jefferson by Rembrandt Peale, 1800.jpg
Nominee John Adams Thomas Jefferson
Party Federalist Democratic-Republican
Home state Massachusetts Virginia
Running mate Thomas Pinckney Aaron Burr
Electoral vote60
Popular vote3,265393
Percentage89.3%10.7%

President before election

George Washington
Independent

Elected President

John Adams
Federalist

The 1796 United States presidential election in New Hampshire took place between November 4 to December 7, 1796, as part of the 1796 United States presidential election to elect the President. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.

Contents

New Hampshire voted for Federalist candidate and Vice President John Adams, over the Democratic-Republican candidate and Secretary of State Thomas Jefferson by a total of 78.6% margin of the popular vote, making this the largest margin for a presidential candidate in the state of New Hampshire.

Results

1796 United States presidential election in New Hampshire [1]
PartyCandidateVotesPercentageElectoral votes
Federalist John Adams 3,26589.3%6
Democratic-Republican Thomas Jefferson 39310.7%
Totals3,658100.0%6

See also

References

  1. "Presidential Results: National, 1796". votearchive.com. Retrieved June 20, 2024.