1824 New Hampshire gubernatorial election

1824 New Hampshire gubernatorial election

←  1823 March 9, 1824 1825  →

Nominee David L. Morril Levi Woodbury Jeremiah Smith Party Democratic-Republican Democratic-Republican Federalist Popular vote 14,985 11,741 3,300 Percentage 49.19% 38.54% 10.83%

County results Morril:     40–50%     50–60%     60–70% Woodbury:     50–60%     60–70%

Governor before election Levi Woodbury Democratic-Republican Elected Governor David L. Morril Democratic-Republican

The 1824 New Hampshire gubernatorial election was held on March 9, 1824, in order to elect the governor of New Hampshire. Former Democratic-Republican United States senator from New Hampshire David L. Morril defeated incumbent Democratic-Republican governor Levi Woodbury and former Federalist governor Jeremiah Smith. Since no candidate received a majority in the popular vote, Morril was elected by the New Hampshire General Court per the state constitution. ^[1]

General election

On election day, March 9, 1824, Democratic-Republican candidate David L. Morril won the popular vote by a margin of 3,244 votes against his foremost opponent and incumbent Democratic-Republican governor Levi Woodbury. But since no candidate received a majority of the popular vote, a separate election was held by the New Hampshire General Court, which chose Morril as the winner, thereby retaining Democratic-Republican control over the office of governor. Morril was sworn in as the 10th governor of New Hampshire on June 2, 1824. ^[2]

Results

New Hampshire gubernatorial election, 1824

Party		Candidate	Votes	%
	Democratic-Republican	David L. Morril	14,985	49.19
	Democratic-Republican	Levi Woodbury (incumbent)	11,741	38.54
	Federalist	Jeremiah Smith	3,300	10.83
		Scattering	438	1.44
Total votes			30,464	100.00
	Democratic-Republican hold

References

1. "David L. Morril". National Governors Association . Retrieved 2024-04-01.
2. "NH Governor". ourcampaigns.com. June 2, 2005. Retrieved 2024-04-01.