1836 New Hampshire gubernatorial election

1836 New Hampshire gubernatorial election

←  1835 March 8, 1836 1837  →

Nominee Isaac Hill Joseph Healey George Sullivan Party Democratic Whig Federalist Popular vote 24,904 2,566 2,230 Percentage 81.22% 8.37% 7.27%

County results Hill:     50–60%     60–70%     80–90%     90-100%

Governor before election William Badger Democratic Elected Governor Isaac Hill Democratic

The 1836 New Hampshire gubernatorial election was held on March 8, 1836 to elect the Governor of New Hampshire. The Democratic former U.S. senator from New Hampshire Isaac Hill defeated the Whig candidate Joseph Healey and the Federalist former Attorney General of New Hampshire George Sullivan. ^[1]

Hill's re-election was considered nearly inevitable, and his opponents struggled to recruit a candidate to contest the election. In March, the Democratic Rhode Island Republican reported that the defunct Federalist Party had nominated Sullivan, but he had declined to run. ^[2]

General election

Results

New Hampshire gubernatorial election, 1836

Party		Candidate	Votes	%
	Democratic	Isaac Hill	24,904	81.22
	Whig	Joseph Healey	2,566	8.37
	Federalist	George Sullivan	2,230	7.27
		Scattering	961	3.14
Total votes			30,661	100.00
	Democratic hold

References

1. "Isaac Hill". National Governors Association . Retrieved April 2, 2024.
2. "The New Hampshire federalists [...]". Rhode Island Republican. March 2, 1836.