1836 New Hampshire gubernatorial election

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1836 New Hampshire gubernatorial election
Flag of New Hampshire.svg
  1835 8 March 1836 1837  
  Isaac Hill, portrait.jpg No image.svg No image.svg
Nominee Isaac Hill Joseph Healey George Sullivan
Party Democratic Whig
Popular vote24,9042,5662,230
Percentage81.22%8.37%7.27%

1836 New Hampshire gubernatorial election results map by county.svg
County results
Hill:     50–60%     60–70%     80–90%     90-100%

Governor before election

William Badger
Democratic

Elected Governor

Isaac Hill
Democratic

The 1836 New Hampshire gubernatorial election was held on 8 March 1836 in order to elect the Governor of New Hampshire. Former Democratic United States Senator from New Hampshire Isaac Hill defeated Whig nominee Joseph Healey and former Federalist Attorney General of New Hampshire George Sullivan. [1]

Contents

General election

On election day, 8 March 1836, Democratic nominee Isaac Hill won the election by a margin of 22,338 votes against his foremost opponent Whig nominee Joseph Healey, thereby retaining Democratic control over the office of Governor. Hill was sworn in as the 16th Governor of New Hampshire on 2 June 1836. [2]

Results

New Hampshire gubernatorial election, 1836
PartyCandidateVotes%
Democratic Isaac Hill 24,904 81.22
Whig Joseph Healey2,5668.37
George Sullivan 2,2307.27
Scattering9613.14
Total votes30,661 100.00
Democratic hold

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References

  1. "Isaac Hill". National Governors Association . Retrieved April 2, 2024.
  2. "NH Governor". ourcampaigns.com. June 3, 2005. Retrieved April 2, 2024.