1930 Rhode Island gubernatorial election

1930 Rhode Island gubernatorial election

←  1928 November 4, 1930 1932  →

Nominee Norman S. Case Theodore F. Green Party Republican Democratic Popular vote 112,070 108,558 Percentage 50.53% 48.95%

County results Municipality results Case:      40–50%     50–60%     60–70%     70–80%     80–90%     90–100% Green:      50–60%     60–70%

Governor before election Norman S. Case Republican Elected Governor Norman S. Case Republican

The 1930 Rhode Island gubernatorial election was held on November 4, 1930. Incumbent Republican Norman S. Case defeated Democratic nominee Theodore F. Green with 50.53% of the vote.

General election

Candidates

Major party candidates

• Norman S. Case, Republican
• Theodore F. Green, Democratic

Other candidates

• Charles H. Dana, Socialist

Results

1930 Rhode Island gubernatorial election ^[1]

Party		Candidate	Votes	%	±%
	Republican	Norman S. Case (incumbent)	112,070	50.53%
	Democratic	Theodore F. Green	108,558	48.95%
	Socialist	Charles H. Dana	1,168	0.53%
Majority			3,512
Turnout
	Republican hold		Swing

References

1. Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN   9780871879967 . Retrieved May 7, 2020.