1833 Rhode Island gubernatorial election

1833 Rhode Island gubernatorial election

←  1832 April 3, 1833 1834  →

Nominee John Brown Francis Lemuel H. Arnold Party Democratic National Republican Popular vote 4,025 3,292 Percentage 54.98% 44.97%

County results Francis:      50–60%     60–70%     70–80% Arnold:      50–60%

Governor before election Lemuel H. Arnold National Republican Elected Governor John Brown Francis Democratic

The 1833 Rhode Island gubernatorial election was held on April 3, 1833, in order to elect the governor of Rhode Island. Democratic nominee and former member of the Rhode Island Senate John Brown Francis defeated incumbent National Republican governor Lemuel H. Arnold. ^[1]

General election

On election day, April 3, 1833, Democratic nominee John Brown Francis won the election by a margin of 733 votes against his opponent incumbent National Republican governor Lemuel H. Arnold, thereby gaining Democratic control over the office of governor. Francis was sworn in as the 13th governor of Rhode Island on May 1, 1833. ^[2]

Results

Rhode Island gubernatorial election, 1833

Party		Candidate	Votes	%
	Democratic	John Brown Francis	4,025	54.98
	National Republican	Lemuel H. Arnold (incumbent)	3,292	44.97
		Scattering	4	0.05
Total votes			7,321	100.00
	Democratic gain from National Republican

References

1. "Lemuel Hastings Arnold". National Governors Association . Retrieved 2024-04-05.
2. "RI Governor". ourcampaigns.com. June 6, 2005. Retrieved 2024-04-05.