1874 Rhode Island gubernatorial election

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1874 Rhode Island gubernatorial election
Flag of Rhode Island.svg
  1873 1 April 1874 1875  
  GovHenryHowardRI.jpg No image.svg
Nominee Henry Howard Lyman Pierce
Party Republican Democratic
Popular vote12,3351,589
Percentage87.48%11.27%

1874 Rhode Island gubernatorial election results map by county.svg
County results
Howard:      60–70%     80–90%     >90%

Governor before election

Henry Howard
Republican

Elected Governor

Henry Howard
Republican

The 1874 Rhode Island gubernatorial election was held on 1 April 1874 in order to elect the governor of Rhode Island. Incumbent Republican governor Henry Howard won re-election against Democratic nominee Lyman Pierce. [1]

Contents

General election

On election day, 1 April 1874, incumbent Republican governor Henry Howard won re-election by a margin of 10,746 votes against his opponent Democratic nominee Lyman Pierce, thereby retaining Republican control over the office of governor. Howard was sworn in for his second term on 5 May 1874. [2]

Results

Rhode Island gubernatorial election, 1874
PartyCandidateVotes%
Republican Henry Howard (incumbent) 12,335 87.48
Democratic Lyman Pierce1,58911.27
Scattering1771.25
Total votes14,101 100.00
Republican hold

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References

  1. "Henry Howard". National Governors Association . Retrieved 8 April 2024.
  2. "RI Governor". ourcampaigns.com. 6 October 2005. Retrieved 8 April 2024.