1873 Rhode Island gubernatorial election

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1873 Rhode Island gubernatorial election
Flag of the United States (1867-1877).svg
  1872 2 April 1873 1874  
  GovHenryHowardRI.jpg No image.svg
Nominee Henry Howard Benjamin G. Chace
Party Republican Democratic
Popular vote9,6563,786
Percentage71.68%28.11%

1873 Rhode Island gubernatorial election results map by county.svg
County results
Howard:      60–70%     70–80%     >90%

Governor before election

Seth Padelford
Republican

Elected Governor

Henry Howard
Republican

The 1873 Rhode Island gubernatorial election was held on 2 April 1873 in order to elect the governor of Rhode Island. Republican nominee Henry Howard defeated Democratic nominee Benjamin G. Chace. [1]

Contents

General election

On election day, 2 April 1873, Republican nominee Henry Howard won the election by a margin of 5,870 votes against his opponent Democratic nominee Benjamin G. Chace, thereby retaining Republican control over the office of governor. Howard was sworn in as the 32nd governor of Rhode Island on 6 May 1873. [2]

Results

Rhode Island gubernatorial election, 1873
PartyCandidateVotes%
Republican Henry Howard 9,656 71.68
Democratic Benjamin G. Chace3,78628.11
Scattering290.21
Total votes13,471 100.00
Republican hold

References

  1. "Henry Howard". National Governors Association . Retrieved April 8, 2024.
  2. "RI Governor". ourcampaigns.com. October 6, 2005. Retrieved April 8, 2024.