1868 Rhode Island gubernatorial election

1868 Rhode Island gubernatorial election

←  1867 1 April 1868 1869  →

Nominee Ambrose Burnside Lyman Pierce Party Republican Democratic Popular vote 10,038 5,731 Percentage 63.61% 36.32%

County results Burnside:      60–70%     80–90%

Governor before election Ambrose Burnside Republican Elected Governor Ambrose Burnside Republican

The 1868 Rhode Island gubernatorial election was held on 1 April 1868 in order to elect the governor of Rhode Island. Incumbent Republican governor Ambrose Burnside won re-election against Democratic nominee Lyman Pierce in a rematch of the 1866 and 1867 election. ^[1]

General election

On election day, 1 April 1868, incumbent Republican governor Ambrose Burnside won re-election by a margin of 6,648 votes against his opponent Democratic nominee Lyman Pierce, thereby retaining Republican control over the office of Governor. Burnside was sworn in for his third term on 4 May 1868.

Results

Rhode Island gubernatorial election, 1868 ^[2]

Party		Candidate	Votes	%
	Republican	Ambrose Burnside (incumbent)	10,038	63.61
	Democratic	Lyman Pierce	5,731	36.32
		Scattering	11	0.07
Total votes			15,780	100.00
	Republican hold

References

1. "Ambrose Burnside". National Governors Association . Retrieved April 7, 2024.
2. United States Gubernatorial Elections 1861-1911 (Michael J. Dubin) Page 478