1936 United States presidential election in Rhode Island

Last updated
1936 United States presidential election in Rhode Island
Flag of Rhode Island.svg
  1932 November 3, 1936 1940  
  Franklin D. Roosevelt - NARA - 196715.jpg LandonPortr.jpg WilliamLemke22.jpg
Nominee Franklin D. Roosevelt Alf Landon William Lemke
Party Democratic Republican Union
Home state New York Kansas North Dakota
Running mate John Nance Garner Frank Knox Thomas C. O'Brien
Electoral vote400
Popular vote165,238125,03119,569
Percentage53.10%40.18%6.29%

Rhode Island Presidential Election Results 1936.svg
County Results

President before election

Franklin D. Roosevelt
Democratic

Elected President

Franklin D. Roosevelt
Democratic

The 1936 United States presidential election in Rhode Island was held on November 3, 1936. The state voters chose four electors to the Electoral College, who voted for president and vice president.

Contents

Rhode Island voted for Democratic Party candidate and incumbent President Franklin D. Roosevelt, who won the state by a margin of 12.92%.

Results

1936 United States presidential election in Rhode Island [1]
PartyCandidateRunning matePopular voteElectoral vote
Count%Count%
Democratic Franklin Delano Roosevelt of New York John Nance Garner of Texas 165,23853.10%4100.00%
Republican Alf Landon of Kansas Frank Knox of Illinois 125,03140.18%00.00%
Union William Lemke of North Dakota Thomas C. O'Brien of Massachusetts 19,5696.29%00.00%
Socialist Labor John W. Aiken of Connecticut Emil F. Teichert of New York 9290.30%00.00%
Communist Earl Russell Browder of Kansas James W. Ford of New York 4110.13%00.00%
Total 311,178100.00%4100.00%

See also

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References

  1. "1936 Presidential General Election Results - Rhode Island". U.S. Election Atlas. Retrieved 23 December 2013.