1860 United States presidential election in Maine

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1860 United States presidential election in Maine
Flag of the United States (1859-1861).svg
  1856 November 2, 1860 1864  
  Abraham Lincoln by Alexander Hesler, 1860-restored (cropped).png Senator Stephen A. Douglas (edited).png John C Breckinridge-04775-restored.jpg
Nominee Abraham Lincoln Stephen A. Douglas John C. Breckinridge
Party Republican Democratic Southern Democratic
Home state Illinois Illinois Kentucky
Running mate Hannibal Hamlin Herschel V. Johnson Joseph Lane
Electoral vote800
Popular vote62,81129,6936,368
Percentage62.24%29.42%6.31%

Maine Presidential Election Results 1860.svg
County Results
Lincoln
  50–60%
  60-70%
  70-80%

The 1860 United States presidential election in Maine took place on November 2, 1860, as part of the 1860 United States presidential election. Voters chose eight electors of the Electoral College, who voted for president and vice president.

Contents

Maine was won by Republican candidate Abraham Lincoln, who won by a margin of 32.82%.

With 62.24% of the popular vote, Maine would prove to be Lincoln's fourth strongest state in terms of popular vote percentage after Vermont, Minnesota and Massachusetts. [1]

Results

1860 United States presidential election in Maine [2]
PartyCandidateRunning matePopular voteElectoral vote
Count%Count%
Republican Abraham Lincoln of Illinois Hannibal Hamlin of Maine 62,81162.24%8100.00%
Democratic Stephen A. Douglas of Illinois Herschel Vespasian Johnson of Georgia 29,69329.42%00.00%
Southern Democratic John Cabell Breckinridge of Kentucky Joseph Lane of Oregon 6,3686.31%00.00%
Constitutional Union John Bell of Tennessee Edward Everett of Massachusetts 2,0462.03%00.00%
Total100,918100.00%8100.00%

See also

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References

  1. "1860 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
  2. "1860 Presidential General Election Results - Maine". U.S. Election Atlas. Retrieved March 17, 2015.