1868 United States presidential election in Iowa

1868 United States presidential election in Iowa

←  1864 November 3, 1868 1872  →

Nominee Ulysses S. Grant Horatio Seymour Party Republican Democratic Home state Illinois New York Running mate Schuyler Colfax Francis Preston Blair Jr. Electoral vote 8 0 Popular vote 120,399 74,040 Percentage 61.92% 38.08%

County Results Grant   50–60%   60–70%   70–80%   80–90%   90–100% Seymour   50–60%   60–70% Tie   ~50%

President before election Andrew Johnson Democratic Elected President Ulysses S. Grant Republican

The 1868 United States presidential election in Iowa took place on November 3, 1868, as part of the 1868 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for president and vice president.

Iowa voted for the Republican nominee, Ulysses S. Grant, over the Democratic nominee, Horatio Seymour. Grant won the state by a margin of 23.84%.

Results

1868 United States presidential election in Iowa [1]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Republican	Ulysses S. Grant of Illinois	Schuyler Colfax of Indiana	120,399	61.92%	8	100.00%
	Democratic	Horatio Seymour of New York	Francis Preston Blair Jr. of Missouri	74,040	38.08%	0	0.00%
Total				194,439	100.00%	8	100.00%

See also

• United States presidential elections in Iowa

References

1. "1868 Presidential General Election Results - Iowa".