1916 Iowa gubernatorial election

1916 Iowa gubernatorial election

←  1914 November 7, 1916 1918  →

Nominee William L. Harding Edwin T. Meredith Party Republican Democratic Popular vote 313,586 186,832 Percentage 61.03% 36.36%

County results Harding:     40–50%     50–60%     60–70%     70–80% Meredith:     50–60%

Governor before election George W. Clarke Republican Elected Governor William L. Harding Republican

The 1916 Iowa gubernatorial election was held on November 7, 1916. Republican nominee William L. Harding defeated Democratic nominee Edwin T. Meredith with 61.03% of the vote.

General election

Candidates

Major party candidates

• William L. Harding, Republican
• Edwin T. Meredith, Democratic

Other candidates

• John W. Bennett, Socialist
• Oren D. Ellett, Prohibition
• Stephen H. Bashor, Progressive
• Arthur S. Dowler, Socialist Labor

Results

1916 Iowa gubernatorial election ^[1]

Party		Candidate	Votes	%	±%
	Republican	William L. Harding	313,586	61.03%
	Democratic	Edwin T. Meredith	186,832	36.36%
	Socialist	John W. Bennett	8,200	1.60%
	Prohibition	Oren D. Ellett	2,880	0.56%
	Progressive	Stephen H. Bashor	2,035	0.40%
	Socialist Labor	Arthur S. Dowler	315	0.06%
Majority			126,754
Turnout
	Republican hold		Swing

References

1. Kalb, Deborah (December 24, 2015). Guide to U.S. Elections. ISBN   9781483380353 . Retrieved July 2, 2020.