1903 Iowa gubernatorial election

1903 Iowa gubernatorial election

←  1901 November 3, 1903 1906  →

Nominee Albert B. Cummins J. B. Sullivan Party Republican Democratic Popular vote 238,804 159,725 Percentage 57.14% 38.22%

County results Cummins:     40–50%     50–60%     60–70%     70–80%     80–90% Sullivan:     40–50%     50–60%

Governor before election Albert B. Cummins Republican Elected Governor Albert B. Cummins Republican

The 1903 Iowa gubernatorial election was held on November 3, 1903. Incumbent Republican Albert B. Cummins defeated Democratic nominee J. B. Sullivan with 57.14% of the vote.

General election

Candidates

Major party candidates

• Albert B. Cummins, Republican
• J. B. Sullivan, Democratic

Other candidates

• John F. Hanson, Prohibition
• John M. Work, Socialist
• Luman Hamlin Weller, People's

Results

1903 Iowa gubernatorial election ^[1]

Party		Candidate	Votes	%	±%
	Republican	Albert B. Cummins (incumbent)	238,804	57.14%
	Democratic	J. B. Sullivan	159,725	38.22%
	Prohibition	John F. Hanson	12,375	2.96%
	Socialist	John M. Work	6,421	1.54%
	Populist	Luman Hamlin Weller	594	0.14%
Majority			79,079
Turnout
	Republican hold		Swing

References

1. Kalb, Deborah (December 24, 2015). Guide to U.S. Elections. ISBN   9781483380353 . Retrieved August 3, 2020.