1899 Iowa gubernatorial election

1899 Iowa gubernatorial election

←  1897 November 7, 1899 1901  →

Nominee L. M. Shaw Frederick Edward White Party Republican Democratic Popular vote 239,464 183,301 Percentage 55.26% 42.30%

County results Shaw:     40-50%     50-60%     60-70%     70-80% White:     40-50%     50-60%

Governor before election L. M. Shaw Republican Elected Governor L. M. Shaw Republican

The 1899 Iowa gubernatorial election was held on November 7, 1899. Incumbent Republican L. M. Shaw defeated Democratic nominee Frederick Edward White with 55.26% of the vote.

General election

Candidates

Major party candidates

• L. M. Shaw, Republican
• Frederick Edward White, Democratic

Other candidates

• Marshall W. Atwood, Prohibition
• Charles Lloyd, People's
• M. J. Kremer, Socialist Labor
• C. C. Heacock, United Christian

Results

1899 Iowa gubernatorial election ^[1]

Party		Candidate	Votes	%	±%
	Republican	L. M. Shaw (incumbent)	239,464	55.26%
	Democratic	Frederick Edward White	183,301	42.30%
	Prohibition	Marshall W. Atwood	7,639	1.76%
	Populist	Charles Lloyd	1,698	0.39%
	Socialist Labor	M. J. Kremer	757	0.18%
	Independent	C. C. Heacock	484	0.11%
Majority			56,163
Turnout
	Republican hold		Swing

References

1. Kalb, Deborah (December 24, 2015). Guide to U.S. Elections. ISBN   9781483380353 . Retrieved August 7, 2020.