1920 Iowa gubernatorial election

1920 Iowa gubernatorial election

←  1918 November 2, 1920 1922  →

Nominee Nathan E. Kendall Clyde L. Herring Party Republican Democratic Popular vote 513,118 338,108 Percentage 58.66% 38.65%

County results Kendall:     40–50%     50–60%     60–70%     70–80% Herring:     50–60%

Governor before election William L. Harding Republican Elected Governor Nathan E. Kendall Republican

The 1920 Iowa gubernatorial election was held on November 2, 1920. Republican nominee Nathan E. Kendall defeated Democratic nominee Clyde L. Herring with 58.66% of the vote.

General election

Candidates

Major party candidates

• Nathan E. Kendall, Republican
• Clyde L. Herring, Democratic

Other candidates

• George J. Peck, Socialist
• Mathis Faber, Farmer–Labor
• J. Jay Hisel, Socialist Labor

Results

1920 Iowa gubernatorial election ^[1]

Party		Candidate	Votes	%	±%
	Republican	Nathan E. Kendall	513,118	58.66%
	Democratic	Clyde L. Herring	338,108	38.65%
	Socialist	George J. Peck	13,671	1.56%
	Farmer–Labor	Mathis Faber	9,153	1.05%
	Socialist Labor	J. Jay Hisel	760	0.09%
Majority			175,010
Turnout
	Republican hold		Swing

References

1. Kalb, Deborah (December 24, 2015). Guide to U.S. Elections. ISBN   9781483380353 . Retrieved June 30, 2020.