1877 Iowa gubernatorial election

1877 Iowa gubernatorial election

←  1875 October 9, 1877 1879  →

Nominee John H. Gear John P. Irish Daniel P. Stubbs Party Republican Democratic Greenback Popular vote 121,316 79,304 34,316 Percentage 49.39% 32.29% 13.97%

County results Gear:     30–40%     40–50%     50–60%     60–70%     70–80%     80–90%     90–100% Irish:     30–40%     40–50%     50–60%     60–70% Stubbs:     50–60%

Governor before election Joshua G. Newbold Republican Elected Governor John H. Gear Republican

The 1877 Iowa gubernatorial election was held on October 9, 1877. Republican nominee John H. Gear defeated Democratic nominee John P. Irish with 49.39% of the vote.

General election

Candidates

Major party candidates

• John H. Gear, Republican
• John P. Irish, Democratic

Other candidates

• Daniel P. Stubbs, Greenback
• Elias Jessup, Prohibition

Results

1877 Iowa gubernatorial election ^[1]

Party		Candidate	Votes	%	±%
	Republican	John H. Gear	121,316	49.39%
	Democratic	John P. Irish	79,304	32.29%
	Greenback	Daniel P. Stubbs	34,316	13.97%
	Prohibition	Elias Jessup	10,565	4.30%
Majority			42,012
Turnout
	Republican hold		Swing

References

1. Kalb, Deborah (December 24, 2015). Guide to U.S. Elections. ISBN   9781483380353 . Retrieved September 21, 2020.