1918 Iowa gubernatorial election

1918 Iowa gubernatorial election

←  1916 November 5, 1918 1920  →

Nominee William L. Harding Claude R. Porter Party Republican Democratic Popular vote 192,662 178,815 Percentage 50.55% 46.92%

County results Harding:     40–50%     50–60%     60–70% Porter:     40–50%     50–60%     60–70%

Governor before election William L. Harding Republican Elected Governor William L. Harding Republican

The 1918 Iowa gubernatorial election was held on November 5, 1918. Republican nominee William L. Harding defeated Democratic nominee Claude R. Porter with 50.55% of the vote.

General election

Candidates

Major party candidates

• William L. Harding, Republican
• Claude R. Porter, Democratic

Other candidates

• Andrew Engle, Socialist
• M. L. Christian, Prohibition

Results

1918 Iowa gubernatorial election ^[1]

Party		Candidate	Votes	%	±%
	Republican	William L. Harding (incumbent)	192,662	50.55%
	Democratic	Claude R. Porter	178,815	46.92%
	Socialist	Andrew Engle	8,005	2.10%
	Prohibition	M. L. Christian	1,625	0.43%
Majority			13,847
Turnout
	Republican hold		Swing

References

1. Kalb, Deborah (December 24, 2015). Guide to U.S. Elections. ISBN   9781483380353 . Retrieved July 1, 2020.