1885 Iowa gubernatorial election

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1885 Iowa gubernatorial election
Flag of Iowa.svg
  1883 November 3, 1885 1887  
  Portrait of William Larrabee.jpg 3x4.svg
Nominee William Larrabee Charles E. Whiting
Party Republican Democratic
Popular vote175,605168,584
Percentage50.76%48.73%

1885 Iowa gubernatorial election results map by county.svg
County results
Larrabee:     40-50%     50-60%     60-70%     70-80%
Whiting:     40-50%     50-60%     60-70%

Governor before election

Buren R. Sherman
Republican

Elected Governor

William Larrabee
Republican

The 1885 Iowa gubernatorial election was held on November 3, 1885. Republican nominee William Larrabee defeated Democratic nominee Charles E. Whiting with 50.76% of the vote.

Contents

General election

Candidates

Major party candidates

Other candidates

Results

1885 Iowa gubernatorial election [1]
PartyCandidateVotes%±%
Republican William Larrabee 175,605 50.76%
Democratic Charles E. Whiting168,58448.73%
Prohibition James Michelwait1,4120.41%
Greenback Elias Doty3140.09%
Majority7,021
Turnout
Republican hold Swing

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References

  1. Kalb, Deborah (24 December 2015). Guide to U.S. Elections. ISBN   9781483380353 . Retrieved August 15, 2020.