1872 United States presidential election in Iowa

1872 United States presidential election in Iowa

←  1868 November 5, 1872 1876  →

Nominee Ulysses S. Grant Horace Greeley Party Republican Liberal Republican Home state Illinois New York Running mate Henry Wilson Benjamin G. Brown Electoral vote 11 0 Popular vote 131,566 81,636 [a] Percentage 60.81% 37.73% [a]

County Results Grant   40–50%   50–60%   60–70%   70–80%   80–90%   90–100% Greeley   50–60%

President before election Ulysses S. Grant Republican Elected President Ulysses S. Grant Republican

The 1872 United States presidential election in Iowa took place on November 5, 1872. All contemporary 37 states were part of the 1872 United States presidential election. The state voters chose 11 electors to the Electoral College, which selected the president and vice president.

Iowa was won by the Republican nominees, incumbent President Ulysses S. Grant of Illinois, and his running mate Senator Henry Wilson of Massachusetts. Grant and Wilson defeated the Liberal Republican and Democratic nominees, former Congressman Horace Greeley of New York and his running mate former Senator and Governor Benjamin Gratz Brown of Missouri.

Grant won the state by a margin of 23.08%.

Results

1872 United States presidential election in Iowa [1]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Republican	Ulysses S. Grant of Illinois	Henry Wilson of Massachusetts	131,566	60.81%	11	100.00%
	Liberal Republican	Horace Greeley of New York	Benjamin Gratz Brown of Missouri	81,636 [a]	37.73% [a]	0	0.00%
	Bourbon Democrat	Charles O'Conor	John Quincy Adams II	2,221	1.03%	0	0.00%
	Write-ins	N/A	N/A	942	0.44%	0	0.00%
Total				216,365	100.00%	11	100.00%

See also

• United States presidential elections in Iowa

Notes

1. Greeley won 71,189 votes (32.9%) as the Liberal nominee, and 10,447 votes (4.83%) as the Liberal Republican Nominee.

References

1. "1872 Presidential General Election Results - Iowa".