1887 Iowa gubernatorial election

1887 Iowa gubernatorial election

←  1885 November 8, 1887 1889  →

Nominee William Larrabee Thomas J. Anderson Party Republican Democratic Popular vote 169,596 153,706 Percentage 50.18% 45.47%

County results Larrabee:     40–50%     50–60%     60–70%     70–80%     80–90% Anderson:     40–50%     50–60%     60–70%     70–80%

Governor before election William Larrabee Republican Elected Governor William Larrabee Republican

The 1887 Iowa gubernatorial election was held on Tuesday November 8, 1887. Incumbent Republican William Larrabee defeated Democratic nominee Thomas J. Anderson with 50.18% of the vote.

General election

Candidates

Major party candidates

• William Larrabee, Republican
• Thomas J. Anderson, Democratic

Other candidates

• M. J. Cain, Union Labor
• V. G. Farnham, Prohibition

Results

1887 Iowa gubernatorial election ^[1]

Party		Candidate	Votes	%	±%
	Republican	William Larrabee (incumbent)	169,596	50.18%
	Democratic	Thomas J. Anderson	153,706	45.47%
	Labor	M. J. Cain	14,283	4.23%
	Prohibition	V. G. Farnham	334	0.10%
Majority			15,890
Turnout
	Republican hold		Swing

References

1. Kalb, Deborah (December 24, 2015). Guide to U.S. Elections. ISBN   9781483380353 . Retrieved August 14, 2020.