1940 Iowa gubernatorial election

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1940 Iowa gubernatorial election
Flag of Iowa (variant).svg
  1938 November 7, 1940 1942  
  George Allison Wilson.jpg John K. Valentine (cropped).png
Nominee George A. Wilson John K. Valentine
Party Republican Democratic
Popular vote620,480553,941
Percentage52.72%47.07%

1940 Iowa gubernatorial election results map by county.svg
County results
Wilson:     40–50%     50–60%     60–70%
Valentine:     50–60%

Governor before election

George A. Wilson
Republican

Elected Governor

George A. Wilson
Republican

The 1940 Iowa gubernatorial election was held on November 5, 1940. Incumbent Republican George A. Wilson defeated Democratic nominee John K. Valentine with 52.72% of the vote.

Contents

Primary elections

Primary elections were held on June 3, 1940. [1]

Democratic primary

Candidates

Results

Democratic primary results [1]
PartyCandidateVotes%
Democratic John K. Valentine 70,233 57.88
Democratic Edward Breen51,11242.12
Total votes121,345 100.00

Republican primary

Candidates

Results

Republican primary results [1]
PartyCandidateVotes%
Republican George A. Wilson (incumbent) 165,176 49.66
Republican H. R. Gross 146,39544.01
Republican Irving H. Knudson21,0396.33
Total votes332,610 100.00

General election

Candidates

Major party candidates

Other candidates

Results

1940 Iowa gubernatorial election [2]
PartyCandidateVotes%±%
Republican George A. Wilson (incumbent) 620,480 52.72%
Democratic John K. Valentine 553,94147.07%
Prohibition M. M. Heptonstall1,2890.11%
Communist Charles Speck1,2300.11%
Majority66,539
Turnout
Republican hold Swing

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References

  1. 1 2 3 "Summary of Official Canvass of Votes Cast in Iowa Primary Election" (PDF). Secretary of State of Iowa. 1940. Retrieved April 18, 2020.
  2. "Summary of Official Canvass of Votes Cast in Iowa General Election" (PDF). Secretary of State of Iowa. 1940. Retrieved April 18, 2020.