1897 Iowa gubernatorial election

1897 Iowa gubernatorial election

←  1895 November 2, 1897 1899  →

Nominee L. M. Shaw Frederick Edward White Party Republican Democratic Popular vote 224,729 194,853 Percentage 51.27% 44.46%

County results Shaw:     40–50%     50–60%     60–70%     70–80% White:     40–50%     50–60%

Governor before election Francis M. Drake Republican Elected Governor L. M. Shaw Republican

The 1897 Iowa gubernatorial election was held on November 2, 1897. Republican nominee L. M. Shaw defeated Democratic nominee Frederick Edward White with 51.27% of the vote.

General election

Candidates

Major party candidates

• L. M. Shaw, Republican
• Frederick Edward White, Democratic

Other candidates

• S. P. Leland, Prohibition
• Charles Lloyd, People's
• John Cliggett, National Democratic
• M. J. Kremer, Socialist Labor

Results

1897 Iowa gubernatorial election ^[1]

Party		Candidate	Votes	%	±%
	Republican	L. M. Shaw	224,729	51.27%
	Democratic	Frederick Edward White	194,853	44.46%
	Prohibition	S. P. Leland	8,243	1.88%
	Populist	Charles Lloyd	5,295	1.21%
	Independent	John Cliggett	4,296	0.98%
	Socialist Labor	M. J. Kremer	876	0.20%
Majority			29,876
Turnout
	Republican hold		Swing

References

1. Kalb, Deborah (December 24, 2015). Guide to U.S. Elections. ISBN   9781483380353 . Retrieved August 8, 2020.