1966 Iowa gubernatorial election

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1966 Iowa gubernatorial election
Flag of Iowa (variant).svg
  1964 November 8, 1966 1968  
  Harold Hughes, US Senator.jpg 3x4.svg
Nominee Harold Hughes William G. Murray
Party Democratic Republican
Popular vote494,259394,518
Percentage55.34%44.17%

1966 Iowa gubernatorial election results map by county.svg
County results
Hughes:      50–60%     60–70%     70–80%
Murray:      40–50%     50–60%     60–70%

Governor before election

Harold Hughes
Democratic

Elected Governor

Harold Hughes
Democratic

The 1966 Iowa gubernatorial election was held on November 8, 1966. Incumbent Democrat Harold Hughes defeated Republican nominee William G. Murray with 55.34% of the vote.

Contents

Primary elections

Primary elections were held on September 6, 1966. [1]

Democratic primary

Candidates

Results

Democratic primary results [1]
PartyCandidateVotes%
Democratic Harold Hughes (incumbent) 80,198 100.00
Total votes80,198 100.00

Republican primary

Candidates

Results

Republican primary results [1]
PartyCandidateVotes%
Republican William G. Murray 87,371 50.5
Republican Robert K. Beck 85,73349.5
Total votes173,109 100.00

General election

Candidates

Major party candidates

Other candidates

Results

1966 Iowa gubernatorial election [2]
PartyCandidateVotes%±%
Democratic Harold Hughes (incumbent) 494,259 55.34%
Republican William G. Murray394,51844.17%
Independent David B. Quiner3,6800.41%
Independent Charles Sloca7150.08%
Majority99,741
Turnout 893,175
Democratic hold Swing

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References

  1. 1 2 3 "Summary of Official Canvass of Votes Cast in Iowa Primary Election" (PDF). Secretary of State of Iowa. 1966. Retrieved March 20, 2020.
  2. "Summary of Official Canvass of Votes Cast in Iowa General Election" (PDF). Secretary of State of Iowa. 1966. Retrieved March 20, 2020.