1912 Vermont gubernatorial election

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1912 Vermont gubernatorial election
Flag of Vermont (1837-1923).svg
  1910 September 3, 1912 (1912-09-03) 1914  
  Allen Miller Fletcher.jpg Harland B. Howe.jpg Fraser Metzger (Vermont clergyman and politician).jpg
Candidate Allen M. Fletcher Harland B. Howe Fraser Metzger
Party Republican Democratic Progressive
Popular vote26,23720,00115,629
Percentage40.5%30.8%24.1%

Governor before election

John A. Mead
Republican

Elected Governor

Allen M. Fletcher
Republican

The 1912 Vermont gubernatorial election took place on September 3, 1912. Incumbent Republican John A. Mead, per the "Mountain Rule", [1] did not run for re-election to a second term as Governor of Vermont. Republican candidate Allen M. Fletcher defeated Democratic candidate Harland B. Howe and Progressive candidate Fraser Metzger to succeed him. Since no candidate won a majority of the popular vote, the election was decided and Fletcher was elected by the Vermont General Assembly in accordance with the state constitution. [2]

Contents

This was the last time until 1986 that none of the gubernatorial candidates received a majority of the vote. [3]

Results

1912 Vermont gubernatorial election [2]
PartyCandidateVotes%±%
Republican Allen M. Fletcher 26,237 40.5
Democratic Harland B. Howe 20,00130.8
Progressive Fraser Metzger 15,62924.1
Prohibition Clement F. Smith 1,7352.7
Socialist Fred W. Suitor 1,2101.9
N/AOther270.0
Total votes'64,839''100'

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References

  1. Hand, Samuel B. "Mountain Rule Revisited" (PDF). Vermont Historical Society. Retrieved 1 January 2015.
  2. 1 2 "General Election Results - Governor - 1789-2012" (PDF). Office of the Vermont Secretary of State. Archived from the original (PDF) on 30 November 2014. Retrieved 1 January 2015.
  3. Doyle 1992, p. 222.

Works cited