1852 United States presidential election in Wisconsin

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1852 United States presidential election in Wisconsin
Flag of the United States (1851-1858).svg
  1848 November 2, 1852 1856  
  Mathew Brady - Franklin Pierce (cropped).jpg Winfield Scott by Fredricks, 1862 (cropped).jpg JP-Hale crop.jpg
Nominee Franklin Pierce Winfield Scott John P. Hale
Party Democratic Whig Free Soil
Home state New Hampshire New Jersey New Hampshire
Running mate William R. King William A. Graham George W. Julian
Electoral vote500
Popular vote33,65822,2108,814
Percentage52.04%34.34%13.63%

Wisconsin Presidential Election Results 1852.svg
County Results

President before election

Millard Fillmore
Whig

Elected President

Franklin Pierce
Democratic

The 1852 United States presidential election in Wisconsin was held on November 2, 1852, as part of the 1852 United States presidential election. State voters chose five electors to the Electoral College, who voted for President and Vice President.

Contents

Democratic Party candidate Franklin Pierce won the state with 52.04 percent of the popular vote, winning Wisconsin's five electoral votes. [1]

This would be the final time a Democratic presidential candidate would win Wisconsin until Grover Cleveland won the state in 1892. No Democratic presidential candidate would again win a majority of Wisconsin's popular vote until Franklin D. Roosevelt in 1932.

Results

1852 United States presidential election in Wisconsin
PartyCandidateRunning matePopular voteElectoral vote
Count%Count%
Democratic Franklin Pierce of New Hampshire William Rufus DeVane King of Alabama 33,65852.04%5100.00%
Whig Winfield Scott of New Jersey William Alexander Graham of North Carolina 22,21034.34%00.00%
Free Soil John Parker Hale of New Hampshire George Washington Julian of Indiana 8,81413.63%00.00%
Total64,682100.00%5100.00%

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References

  1. "1852 Presidential General Election Results – Wisconsin" . Retrieved August 17, 2016.