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| Elections in Wisconsin |
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The 1918 Wisconsin lieutenant gubernatorial election was held on November 5, 1918, in order to elect the lieutenant governor of Wisconsin. Incumbent Republican lieutenant governor Edward Dithmar defeated Democratic nominee John W. Hogan, Socialist nominee and former member of the Wisconsin State Assembly James Vint and Prohibition nominee Clyde D. Mead.
The Republican primary election was held on September 3, 1918. Incumbent lieutenant governor Edward Dithmar received a plurality of the votes (44.94%) against incumbent state senator Charles H. Everett and candidate Harley Nickerson, and was thus elected as the nominee for the general election. [1]
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | Edward Dithmar (incumbent) | 74,402 | 44.94% | |
| Republican | Charles H. Everett | 53,266 | 32.17% | |
| Republican | Harley Nickerson | 37,895 | 22.89% | |
| Total votes | 165,563 | 100.00% | ||
On election day, November 5, 1918, incumbent Republican lieutenant governor Edward Dithmar won re-election by a margin of 72,512 votes against his foremost opponent Democratic nominee John W. Hogan, thereby retaining Republican control over the office of lieutenant governor. Dithmar was sworn in for his third term on January 6, 1919. [2]
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | Edward Dithmar (incumbent) | 165,401 | 51.72 | |
| Democratic | John W. Hogan | 92,889 | 29.05 | |
| Socialist | James Vint | 56,374 | 17.63 | |
| Prohibition | Clyde D. Mead | 5,084 | 1.59 | |
| Scattering | 31 | 0.01 | ||
| Total votes | 319,779 | 100.00 | ||
| Republican hold | ||||
