Hobart Township, Lake County, Indiana

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Hobart Township
Township
Map highlighting Hobart Township, Lake County, Indiana.svg
Coordinates: 41°32′48″N87°15′53″W / 41.54667°N 87.26472°W / 41.54667; -87.26472
Country United States
State Indiana
County Lake
Government
 • Type Indiana township
Area
 • Total25.98 sq mi (67.3 km2)
 • Land25.47 sq mi (66.0 km2)
 • Water0.51 sq mi (1.3 km2)
Elevation
[1]
627 ft (191 m)
Population
 (2020) [2]
 • Total40,652
 • Density1,547.4/sq mi (597.5/km2)
FIPS code 18-34132 [3]
GNIS feature ID 453414

Hobart Township is one of eleven townships in Lake County, Indiana. As of the 2010 census, its population was 39,417 and it contained 16,366 housing units. [4]

Contents

Geography

According to the 2010 census, the township has a total area of 25.98 square miles (67.3 km2), of which 25.47 square miles (66.0 km2) (or 98.04%) is land and 0.51 square miles (1.3 km2) (or 1.96%) is water. [4]

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References

  1. ↑ "US Board on Geographic Names". United States Geological Survey. October 25, 2007. Retrieved January 31, 2008.
  2. ↑ "Census Bureau profile: Hobart Township, Lake County, Indiana". United States Census Bureau. May 2023. Retrieved March 15, 2024.
  3. ↑ "U.S. Census website". United States Census Bureau . Retrieved January 31, 2008.
  4. 1 2 "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Archived from the original on February 12, 2020. Retrieved May 10, 2013.


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