1817 Georgia gubernatorial election

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1817 Georgia gubernatorial election
Flag of Georgia (U.S. state).svg
  1815 10 November 1817 1819  
  No image.svg John Clark.jpg
Nominee William Rabun John Clark
Party Democratic-Republican Democratic-Republican
Popular vote6257
Percentage52.10%47.90%

Governor before election

William Rabun (Acting)
Democratic-Republican

Elected Governor

William Rabun
Democratic-Republican

The 1817 Georgia gubernatorial election was held on 10 November 1817 in order to elect the Governor of Georgia. Democratic-Republican candidate and incumbent acting Governor William Rabun defeated fellow Democratic-Republican candidate John Clark in a Georgia General Assembly vote. [1]

Contents

General election

On election day, 10 November 1817, Democratic-Republican candidate William Rabun won the election against his opponent fellow Democratic-Republican candidate John Clark. Rabun was officially sworn in as the 29th Governor of Georgia on 10 November 1817. [2]

Results

Georgia gubernatorial election, 1817 [3]
PartyCandidateVotes%
Democratic-Republican William Rabun 62 52.10
Democratic-Republican John Clark 5747.90
Total votes119 100.00
Democratic-Republican hold

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References

  1. "Georgia 1817 Governor". Tufts Digital Collations and Archives. A New Nation Votes: American Election Returns 1787–1825. Tufts University . Retrieved 8 December 2023.
  2. "GA Governor". ourcampaigns.com. 18 July 2022. Retrieved 8 December 2023.
  3. Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson: McFarland & Company. ISBN   9780786414390.