1867 Minnesota Attorney General election

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1867 Minnesota Attorney General election
Flag of Minnesota.svg
  1865 November 5, 1867 1869  
  FrancesRECornell.jpg Andrew G. Chatfield (Minnesota Supreme Court).png
Nominee Francis R. E. Cornell Andrew G. Chatfield
Party Republican Democratic
Popular vote34,65728,918
Percentage53.84%44.92%

Attorney General before election

William J. Colvill
National Union

Elected Attorney General

Francis R. E. Cornell
Republican

The 1867 Minnesota Attorney General election was held on November 5, 1867, in order to elect the attorney general of Minnesota. Republican nominee and former member of the Minnesota House of Representatives Francis R. E. Cornell defeated Democratic nominee and former Justice of the Supreme Court of Minnesota Territory Andrew G. Chatfield. [1]

Contents

General election

On election day, November 5, 1867, Republican nominee Francis R. E. Cornell won the election by a margin of 5,739 votes against his opponent Democratic nominee Andrew G. Chatfield, thereby gaining Republican control over the office of attorney general. Cornell was sworn in as the 4th attorney general of Minnesota on January 8, 1868. [2]

Results

Minnesota Attorney General election, 1867
PartyCandidateVotes%
Republican Francis R. E. Cornell 34,657 53.84
Democratic Andrew G. Chatfield 28,91844.92
Write-in 8011.24
Total votes64,376 100.00
Republican gain from National Union

References

  1. "Attorney General, 1867 Election". electionarchives.lib.umn.edu. Retrieved 2024-10-05.
  2. "MN Attorney General". ourcampaigns.com. March 19, 2024. Retrieved 2024-10-05.