1988 Missouri Attorney General election

1988 Missouri Attorney General election

←  1984 November 8, 1988 1992  →

Nominee William L. Webster Michael A. Wolff Party Republican Democratic Popular vote 1,224,346 796,217 Percentage 60.59% 39.41%

County results Webster:     50–60%     60–70%     70–80% Wolff:     50–60%     60–70%

Attorney General before election William L. Webster Republican Elected Attorney General William L. Webster Republican

The 1988 Missouri Attorney General election was held on November 8, 1988, in order to elect the attorney general of Missouri. Republican nominee and incumbent attorney general William L. Webster defeated Democratic nominee Michael A. Wolff. ^[1]

General election

On election day, November 8, 1988, Republican nominee William L. Webster won re-election by a margin of 428,129 votes against his opponent Democratic nominee Michael A. Wolff, thereby retaining Republican control over the office of attorney general. Webster was sworn in for his second term on January 9, 1989. ^[2]

Results

Missouri Attorney General election, 1988

Party		Candidate	Votes	%
	Republican	William L. Webster (incumbent)	1,224,346	60.59
	Democratic	Michael A. Wolff	796,217	39.41
Total votes			2,020,563	100.00
	Republican hold

See also

• 1988 Missouri gubernatorial election

References

1. "1988 Attorney General General Election Results - Missouri". uselectionatlas.org. December 20, 2012. Retrieved 2024-10-27.
2. "MO Attorney General". ourcampaigns.com. February 12, 2018. Retrieved 2024-10-27.